A) \[{{I}_{2}}\]
B) \[{{I}_{3}}^{-}\]
C) \[{{I}^{-}}\]
D) None of these
Correct Answer: C
Solution :
Key Idea: Electron donors are Lewis base. In the reaction \[{{I}_{2}}+{{I}^{-}}\xrightarrow{{}}{{I}^{3-}},{{I}^{-}}\] donates a pair of electron and 12 accepts it to form \[{{I}^{3-}}\] \[\therefore \] \[{{I}^{-}}\] is Lewis base.
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