BCECE Medical BCECE Medical Solved Papers-2005

  • question_answer
    A reaction \[A\xrightarrow{{}}B\] follows a second order kinetic. Doubling the concentration of A will increase the rate of formation of B by a factor of:

    A)  1/4           

    B)  4

    C)  1/2           

    D)  2

    Correct Answer: B

    Solution :

    Key Idea: For second order reaction                 \[r=k\,{{[A]}^{2}}\] ... (i) When concentration of A (reactant) is doubled                 \[r=k\,{{[2\,A]}^{2}}\]                 \[r=4\,k\,{{[A]}^{2}}\] ... (ii) Comparing Eqs. (i) and (ii) \[r=4\,\,r\]


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