BCECE Medical BCECE Medical Solved Papers-2006

  • question_answer
    A boy begins to walk eastward along a street infront of his house, and the graph of his displacement from home is shown in the following figure. His average velocity for the whole time interval is equal to:

    A)  8 m/min      

    B)  6 m/min

    C)  \[\frac{8}{3}\] m/min      

    D)  2 m/min

    Correct Answer: D

    Solution :

    Key Idea : The average velocity is defined as total displacement of the body in a particular time interval divided by the time interval. Displacement from 0 to 5 s = 40 m Displacement from 5 to 10 s = 40 m Displacement from 0 to 15 s = - 20m  and displacement from 15 to 20 s = 0 m \[\therefore \] Net displacement                 = 40 + 40 - 20 + 0 = 60m Total time taken = 5 + 5 + 15 + 5 = 30 min Hence, average velocity \[=\frac{displacement\text{ (}m)}{time\,\,(\min )}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner