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BCECE Medical BCECE Medical Solved Papers-2006

  • question_answer
    The equilibrium constant \[{{K}_{p}}\] for the reaction, \[{{H}_{2}}(g)+{{I}_{2}}(g)2HI(g)\] is:

    A)  more than one  

    B)  less than one

    C)  equal to \[{{K}_{c}}\]     

    D)  zero

    Correct Answer: C

    Solution :

    \[{{H}_{2}}(g)+{{I}_{2}}(g)2HI(g)\] We know that, \[{{K}_{p}}={{K}_{c}}\,{{(RT)}^{\Delta {{n}_{g}}}}\] Here,     \[\Delta {{n}_{g}}=2-2=0\] \[\therefore \] \[{{K}_{p}}={{K}_{c}}\,\,{{(RT)}^{0}}={{K}_{c}}\]


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