A) 2.2 m/s
B) 1.8 m/s
C) 1.4 m/s
D) 0.6 m/s
Correct Answer: C
Solution :
Key Idea: Total energy remains conserved in simple harmonic motion. The bob possess kinetic energy at its mean position which gets converted to potential energy at height h. But the total energy remains conserved. Hence, we have KE = PE Let velocity of bob at mean position to v and m be its mass, then we have \[\frac{1}{2}m{{v}^{2}}=mgh\] Putting g = 9.8 \[m/{{s}^{2}}\], h = 0.1 m \[\therefore \] \[v=\sqrt{9.8\times 0.1}=1.4\,m/s\].You need to login to perform this action.
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