A) \[{{[Ni{{(CN)}_{4}}]}^{2-}}\]
B) \[[Ni{{(CO)}_{4}}]\]
C) \[{{[Ni{{(Cl)}_{4}}]}^{2-}}\]
D) All of the above
Correct Answer: A
Solution :
Key Idea: Draw the excited state and find hybridisation in order to find shape of molecule. \[Ni(CN)_{4}^{2-}\]
\[{{[NiC{{l}_{4}}]}^{2-}}\] Ni is in +2 oxidation state. 
\[NiC{{(CO)}_{4}}\] Tetrahedral shape Oxidation state of Ni is zero 
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