A) \[8\times {{10}^{5}}J\]
B) \[16\times {{10}^{5}}J\]
C) \[12\times {{10}^{5}}J\]
D) \[32\times {{10}^{5}}J\]
Correct Answer: C
Solution :
Work done \[W=mgh+\Delta pV\] \[=V\rho gh+\Delta \,pV\] Here, \[V=4\,{{m}^{3}},\rho ={{10}^{3}}kg/{{m}^{3}},g=10\,m/{{s}^{2}}\], \[h=20\,m,\,\Delta p=(2\times {{10}^{5}}-1\times {{10}^{5}})N/{{m}^{2}}\] \[\therefore \] \[W=4\times {{10}^{3}}\times 10\times 20\] \[+(2\times {{10}^{5}}-1\times {{10}^{5}})\times 4\] \[=8\times {{10}^{5}}+4\times {{10}^{5}}\] \[=12\times {{10}^{5}}J\]
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