A) \[3.12\times {{10}^{13}}\]
B) \[3.12\times {{10}^{3}}\]
C) \[3.1\times {{10}^{17}}\]
D) \[3.12\times {{10}^{19}}\]
Correct Answer: A
Solution :
Total energy/s = 1000 J Energy released/fission = 200 MeV \[=200\times 1.6\times {{10}^{-13}}J\] \[=3.2\times {{10}^{-11}}J\] \[\therefore \] Number of fission/s \[=\frac{1000}{3.2\times {{10}^{-11}}}\] \[=3.2\times {{10}^{13}}\]
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