A) 10.3 m/s
B) 2.8 m/s
C) 5.6 m/s
D) 8.4 m/s
Correct Answer: A
Solution :
Bernoullis equation tor flowing liquid be written as \[p+\frac{1}{2}\rho {{v}^{2}}+\rho gh=\] constant ... (i) Here, p = pressure energy per unit volume of liquid \[\rho =\] density of liquid (water) h = height of liquid column v = velocity of liquid and g = acceleration due to gravity Dividing the Eq. (i) by \[\rho g\], we have \[\frac{p}{\rho g}+\frac{{{v}^{2}}}{2g}+h=\] constant In this expression, \[\frac{{{v}^{2}}}{2g}\] is velocity head and \[\frac{p}{\rho g}\] is pressure head. It is given that, Velocity head = pressure head Ie, \[\frac{{{v}^{2}}}{2g}=\frac{p}{\rho g}\] or \[{{v}^{2}}=\frac{2p}{\rho }\] or \[=\frac{2\times 13.6\times {{10}^{3}}\times 40\times {{10}^{-2}}\times 9.8}{{{10}^{3}}}\] \[\therefore \] v= 10.32 m/s
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