BCECE Medical BCECE Medical Solved Papers-2009

  • question_answer
    Ethyl chloride on treatment with alcoholic alkali gives

    A)  \[{{C}_{2}}{{H}_{6}}\]

    B)  \[C{{H}_{3}}CHO\]

    C)  \[{{C}_{2}}{{H}_{5}}OH\]

    D)   \[C{{H}_{2}}=C{{H}_{2}}\]

    Correct Answer: D

    Solution :

    Alcoholic alkali acts as dehydrohalogenating agent. \[\underset{ethyl\text{ }chloride}{\mathop{{{C}_{2}}{{H}_{5}}Cl}}\,\xrightarrow[\begin{smallmatrix}  -KCl \\  -{{H}_{2}}O \end{smallmatrix}]{Alc.\,\,(KOH)}\underset{ethylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\]


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