A) \[\frac{1}{2}\,pV\]
B) \[pV\]
C) \[2pV\]
D) \[4pV\]
Correct Answer: D
Solution :
Two slabs each of length d and same areas and thermal conductivities \[{{K}_{1}}\] and \[{{K}_{2}}\] are connected in parallel, then Heat current \[H={{H}_{1}}+{{H}_{2}}\] \[\frac{K(2A)\,({{\theta }_{1}}-{{\theta }_{2}})}{2}=\frac{{{K}_{1}}A({{\theta }_{1}}-{{\theta }_{2}})}{d}+\frac{{{K}_{2}}A({{\theta }_{1}}-{{\theta }_{2}})}{d}\] \[\Rightarrow \] \[K=\frac{{{K}_{1}}+{{K}_{2}}}{2}\]
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