A) \[{{K}_{2}}C{{O}_{3}}\] is fairly soluble in water
B) it has no water of crystallisation
C) \[KHC{{O}_{3}}\] is highly soluble in water
D) \[{{K}_{2}}C{{O}_{3}}\] decomposes in \[{{H}_{2}}O\])
Correct Answer: C
Solution :
Solvay-ammonia process involves the formation of bicarbonate and bicarbonate of potassium, ie, \[KHC{{O}_{3}}\], is highly soluble in water. Thats why \[{{K}_{2}}C{{O}_{3}}\] cannot be prepared by Solvay-ammonia process.
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