A) \[0.24\times {{10}^{-12}}N\]
B) \[2.4\times {{10}^{-12}}\text{ }N\]
C) \[24\times {{10}^{12}}N~\]
D) \[0.024\times {{10}^{12}}\text{ }N\]
Correct Answer: B
Solution :
Magnetic force, \[F=qv\,B\sin \theta \] \[\therefore \]\[F=(1.6\times {{10}^{-19}})\times (2\times {{10}^{7}})\times (1.5)\sin {{30}^{o}}\]\[F=1.6\times {{10}^{-12}}\times 2\times 1.5\times \frac{1}{2}\] \[F=2.4\times {{10}^{-12}}N\]
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