A) \[\frac{f}{2}\]
B) \[f\]
C) \[2f\]
D) \[4f\]
Correct Answer: C
Solution :
According to Lens Makers formula, \[\frac{1}{f}=(\mu -1)\left( \frac{1}{R}-\frac{1}{-R} \right)\] \[\Rightarrow \] \[\frac{1}{f}=(\mu -1)\left( \frac{2}{R} \right)\] ? (i) On cutting, \[\frac{1}{f}=(\mu -1)\left( \frac{1}{R}-\frac{1}{\infty } \right)\] \[\frac{1}{f}=(\mu -1)\left( \frac{1}{R} \right)\] ? (ii) From Eqs. (i) and (ii), we get \[f=2f\]
You need to login to perform this action.
You will be redirected in
3 sec
