A) 1020 eV
B) 2040 eV
C) 0.51 eV
D) 0.102 eV
Correct Answer: A
Solution :
For hydrogen atom, energy difference \[\Delta {{E}_{H}}=Rhc\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] For other atoms, \[\Delta E={{Z}^{2}}Rhc\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)={{Z}^{2}}\Delta {{E}_{H}}\] \[={{(10)}^{2}}\times 10.2\] = 1020eV
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