BCECE Medical BCECE Medical Solved Papers-2010

  • question_answer
    The activity of a radioactive sample is measured as 9750 count/min at t = 0 and 975 count/min att = 5min. The decay constant is nearly

    A)  0.922 \[{{\min }^{-1}}\]

    B)  0.691 \[{{\min }^{-1}}\]

    C)  0.461 \[{{\min }^{-1}}\]

    D)  0.230 \[{{\min }^{-1}}\]

    Correct Answer: C

    Solution :

    Activity, \[A={{A}_{0}}{{e}^{-\lambda t}}\] \[\therefore \] \[975=9750{{e}^{-\lambda \times 5}}\]                 \[\frac{1}{10}={{e}^{-\lambda \times 5}}\] Taking logarithm on both sides, we have                 \[-{{\log }_{e}}10=-5\,\lambda \]                 \[-2.3026=-5\lambda \] \[\lambda =\frac{2.3026}{5}=0.46\,{{\min }^{-1}}\]


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