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BCECE Medical BCECE Medical Solved Papers-2010

  • question_answer
    A pipe opened at both ends produces a note of frequency \[{{f}_{1}}\]. When the pipe is kept with \[\frac{3}{4}\] th of its length in water, it produces a note of frequency \[{{f}_{2}}\]. The ratio \[\frac{{{f}_{1}}}{{{f}_{2}}}\] is

    A)  \[\frac{3}{4}\]                 

    B)  \[\frac{4}{3}\]

    C)  \[\frac{1}{2}\]

    D)  2

    Correct Answer: C

    Solution :

    For open pipe \[{{f}_{1}}=\frac{v}{2l}\] and for closed pipe                 \[{{f}_{2}}=\frac{v}{4\times \left( \frac{l}{4} \right)}=\frac{v}{l}=2{{f}_{1}}\] \[\Rightarrow \] \[\frac{{{f}_{1}}}{{{f}_{2}}}=\frac{1}{2}\]


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