BCECE Medical BCECE Medical Solved Papers-2010

  • question_answer
    A solenoid is 1.5 m long and its inner diameter is 4.0 cm. It has 3 layers of windings of 1000 turns each and carries a current of 2.0 A. The magnetic flux for a cross-section of the solenoid is nearly

    A)  \[4.1\times {{10}^{-5}}\] Wb 

    B)  \[5.2\times {{10}^{-5}}\] Wb

    C)  \[6.31\times {{10}^{-3}}\] Wb  

    D)  \[2.5\times {{10}^{-7}}\] Wb

    Correct Answer: C

    Solution :

    Magnetic flux is a measure of the quantity of magnetism, taking account of the strength and extent of magnetic field. \[\phi =nBA\] where n is number of turns, B is magnetic field and A is area. Given, \[n=1000,\,i=2A,\,r=2\times {{10}^{-2}}m\], Also magnetic field B of a solenoid of length \[l\]is \[B=\frac{{{\mu }_{0}}ni}{l}\] \[\therefore \] \[\phi =\frac{{{\mu }_{0}}{{n}^{2}}iA}{l}\] \[=\frac{3\times {{10}^{-7}}\times 4\pi \times {{(100)}^{2}}\times 2\times \pi \,{{(2\times {{10}^{-2}})}^{2}}}{1.5}\] \[\phi =6.31\times {{10}^{-3}}Wb\]


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