A) \[CuS{{O}_{4}}\]
B) \[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\]
C) \[ZnS{{O}_{4}}\]
D) \[FeS{{O}_{4}}\]
Correct Answer: A
Solution :
\[2CuS{{O}_{4}}+4KI\xrightarrow{{}}C{{u}_{2}}{{I}_{2}}+{{I}_{2}}+2{{K}_{2}}S{{O}_{4}}\] \[{{I}^{-}}\] being strong reducing agent reduces \[C{{u}^{2+}}\]^ ion into \[C{{u}^{+}}\].
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