A) \[C{{H}_{3}}CHO;C{{H}_{3}}COCH=C{{H}_{2}}\]
B) \[C{{H}_{3}}CH=\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,-CHO;C{{H}_{2}}O\]
C) \[C{{H}_{3}}CHO;C{{H}_{3}}COCHO;C{{H}_{2}}O\]
D) \[C{{H}_{3}}CHO;C{{H}_{3}}COC{{H}_{2}};C{{H}_{2}}O\]
Correct Answer: C
Solution :
When an alkene is subjected to reductive ozonolysis, the double bond breaks and two O atoms are attached to the double bonded carbon atoms in the final product. Thus, \[\underset{ethanal}{\mathop{C{{H}_{3}}\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}\,=O}}\,+O=\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,-CH=O+\,\,\underset{formaldehyde}{\mathop{O=\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}\,H}}\,\] \[\xrightarrow{{}}\,\,\,C{{H}_{3}}CH=\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}\,-CH=C{{H}_{2}}\]
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