A) \[HCHO\]
B) \[C{{H}_{3}}COOH\]
C) \[C{{H}_{3}}C{{H}_{2}}COOH\]
D) \[{{C}_{6}}{{H}_{5}}COOH\]
Correct Answer: A
Solution :
Aldehydes having lack of \[\alpha \]-H atom react with\[NaOH\] and produce an acid and an alcohol. Thus, HCHO gives an acid and an alcohol when treated with \[NaOH\]. \[2HCHO\xrightarrow{NaOH}HCOOH+C{{H}_{3}}OH\] (This is Cannizaro reaction)
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