A) nitroethane
B) methylcyanide
C) methylisocyanide
D) nitrobenzene
Correct Answer: C
Solution :
Reduction of nitroethane \[({{C}_{2}}{{H}_{5}}N{{O}_{2}})\], methylcyanide \[(C{{H}_{3}}CN)\] and nitrobenzene \[({{C}_{6}}{{H}_{5}}N{{O}_{2}})\] gives \[{{1}^{o}}\] amine, while reduction of isocyanide gives \[{{2}^{o}}\] amine. \[C{{H}_{3}}N\overset{=}{\mathop{\to }}\,C\xrightarrow{LiAl{{H}_{4}}}\underset{{{\text{2}}^{o}}\text{ }amine}{\mathop{C{{H}_{3}}NHC{{H}_{3}}}}\,\]
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