BCECE Medical BCECE Medical Solved Papers-2011

  • question_answer
    Two discs have same mass and thickness Their materials are of densities \[{{\rho }_{1}}\] and \[{{\rho }_{2}}\]. The ratio of their moment of inertia about central axis will be

    A)  \[{{\rho }_{1}}:{{\rho }_{2}}\]          

    B)  \[{{\rho }_{1}}:{{\rho }_{2}}:1\]

    C)  \[1:{{\rho }_{1}}\,\,{{\rho }_{2}}\]

    D)  \[{{\rho }_{2}}:{{\rho }_{1}}\]

    Correct Answer: D

    Solution :

    Moment of inertia of disc                 \[I=\frac{1}{2}M{{R}^{2}}=\frac{1}{2}M\,\left( \frac{M}{\pi \rho t} \right)\] \[\therefore \] \[I=\frac{1}{2}\frac{{{M}^{2}}}{\pi \rho {{t}^{2}}}\] \[\left( As\,\,\rho =\frac{Mass}{Volume}=\frac{M}{\pi {{R}^{2}}t},\,\,therefore,\,{{R}^{2}}=\frac{M}{\pi \rho t} \right)\] \[\therefore \] \[I\propto \frac{1}{\rho }\] (If M and t are constants) \[\Rightarrow \] \[\frac{{{I}_{1}}}{{{I}_{2}}}=\frac{{{\rho }_{2}}}{{{\rho }_{1}}}\]


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