A) \[1.1\times {{10}^{9}}\]
B) \[6.7\times {{10}^{9}}\]
C) \[4\times {{10}^{19}}\]
D) \[5\times {{10}^{19}}\]
Correct Answer: B
Solution :
Charge \[q=CV\] or \[ne=CV\] \[\therefore \] The number of electron \[n=\frac{CV}{e}=\frac{90\times {{10}^{-12}}\times 12}{1.6\times {{10}^{-19}}}\] \[=6.7\times {{10}^{9}}\] electrons
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