BCECE Medical BCECE Medical Solved Papers-2011

  • question_answer
    R is a radius of a planet and p is its density. The escape velocity on its surface will be

    A)  \[{{R}^{2}}\sqrt{4\pi G\rho /3}\]

    B)  \[R\sqrt{4\pi G\rho /3}\]

    C)  \[{{R}^{2}}\sqrt{8\pi G\rho /3}\]

    D)  \[R\sqrt{8\pi G\rho /3}\]

    Correct Answer: D

    Solution :

    Escape velocity \[v=\sqrt{\frac{2GM}{R}}\] \[=\sqrt{\frac{2G\times \frac{4}{3}\pi {{R}^{3}}\rho }{R}}=R\sqrt{\frac{8}{3}\pi G\rho }\]


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