A) 2 A
B) \[200\sqrt{2}\,A\]
C) \[100\sqrt{2}\,A\]
D) 1.41 A
Correct Answer: D
Solution :
\[e=200\sin 1000\,\pi \,t,\,\omega =100\,\pi \] \[\Rightarrow \] \[f=\frac{\omega }{2\pi }=500\,Hz\] \[{{e}_{0}}=200\,\,V\] At resonance Z = R So, \[{{i}_{0}}=\frac{200}{R}=\frac{200}{100}=2\,A\] \[{{i}_{rms}}=\frac{{{i}_{0}}}{\sqrt{2}}=\frac{2}{\sqrt{2}}=\sqrt{2}=1.41\,A\]
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