A) \[{{({{N}_{1}}/{{N}_{2}})}^{2/3}}\]
B) \[{{({{N}_{1}}/{{N}_{2}})}^{3/2}}\]
C) \[{{({{N}_{2}}/{{N}_{1}})}^{2/3}}\]
D) \[{{({{N}_{2}}/{{N}_{1}})}^{3/2}}\]
Correct Answer: C
Solution :
According to Keplers law of planetary motion \[{{T}^{2}}\propto {{R}^{3}}\] If N is the frequency then \[{{N}^{2}}\propto {{(R)}^{-3}}\] or \[\frac{{{N}_{2}}}{{{N}_{1}}}={{\left( \frac{{{R}_{2}}}{{{R}_{1}}} \right)}^{-3/2}}\] \[\Rightarrow \] \[\frac{{{R}_{1}}}{{{R}_{2}}}={{\left( \frac{{{N}_{2}}}{{{N}_{1}}} \right)}^{2/3}}\]You need to login to perform this action.
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