A) zero
B) \[2.88\times {{10}^{11}}N/C\]
C) \[1.44\times {{10}^{11}}N/C\]
D) \[5.76\times {{10}^{11}}N/C\]
Correct Answer: C
Solution :
\[E=9\times {{10}^{9}}\times \frac{q}{n}=9\times {{10}^{9}}\frac{1.6\times {{10}^{-19}}}{{{(1\times {{10}^{-10}})}^{2}}}\] \[=1.44\times {{10}^{11}}M/C\]
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