A) 245\[\pi \] as shunt
B) 2450\[\pi \] as series
C) 2500\[\pi \] as shunt.
D) 2550\[\pi \] in series
Correct Answer: B
Solution :
Given \[{{R}_{q}}=50\,\,\Omega \], \[{{l}_{g}}=25\times 4\times {{10}^{-4}}A={{10}^{-2}}A\] Range of V = 25 volts Resistance, \[R=\frac{V}{{{l}_{g}}}-{{R}_{q}}=\left( \frac{25}{{{10}^{-2}}}-50 \right)\,\,\Omega \] \[=2450\,\,\Omega \] Thus, a resistance of \[2450\,\,\Omega \] is connected is series to convert it into a voltmeter.
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