BCECE Medical BCECE Medical Solved Papers-2013

  • question_answer
    In a Daniell cell constructed in the laboratory, the voltage observed was 0.9 V instead of 1.1 V of the standard cell. A possible explanation is

    A)  \[[Z{{n}^{2+}}]>[C{{u}^{2+}}]\]

    B)  \[[Z{{n}^{2+}}]<[C{{u}^{2+}}]\]

    C)  Zn electrode has twice the surface of Cu electrode

    D)  mol ratio of \[Z{{n}^{2+}}:\,C{{u}^{2+}}\] is \[2:1\]  

    Correct Answer: A

    Solution :

    \[{{E}_{cell}}=E_{cell}^{o}=-\frac{0.0591}{2}\log \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}\]                 \[=1.1-\frac{0.0591}{2}\log \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}\] \[{{E}_{cell}}<1.1\] if \[\frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}>1\]


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