A) \[NaCl\]
B) \[NaH\]
C) \[LiH\]
D) \[HCOONa\]
Correct Answer: B
Solution :
In Nelsons cell, \[{{H}_{2}}\] gas is liberated at cathode wheres \[C{{l}_{2}}\] gas is liberated at anode, on electrolysis of solution of NaCI. \[NaClN{{a}^{+}}+C{{l}^{-}}\] \[{{H}_{2}}O{{H}^{+}}+O{{H}^{-}}\] at cathode \[{{H}^{+}}+{{e}^{-}}\xrightarrow{{}}H\] \[H+H\xrightarrow{{}}{{H}_{2}}\uparrow \] at anode \[C{{l}^{-}}\xrightarrow{{}}Cl+{{e}^{-}}\] \[Cl+Cl\xrightarrow{{}}C{{l}_{2}}\uparrow \]
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