question_answer

\[{{H}_{2}}{{O}_{2}}\] oxidises \[Mn{{O}_{2}}\] is \[MnO_{4}^{-}\] in basic medium, \[{{H}_{2}}{{O}_{2}}\] and \[Mn{{O}_{2}}\] react in the molar ratio of

A)  1 : 1     

B)  2 : 1    

C)  2 : 3    

D)  3 : 2

Correct Answer: D

Solution :

(Oxidation number two 0 atoms taken) On balancing of oxidation number \[3{{H}_{2}}{{O}_{2}}+2Mn{{O}_{2}}\xrightarrow{{}}2MnO_{4}^{-}+6{{H}_{2}}O\] Thus. \[{{H}_{2}}{{O}_{2}}:Mn{{O}_{2}}=3:2\]