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BCECE Medical BCECE Medical Solved Papers-2014

  • question_answer
    Thermal conductivity of a material in CGS system is 0.4. In steady state, the rate of flow of heat is 10\[cal/s-c{{m}^{2}}\]. The thermal gradient will be

    A)  \[{{5}^{o}}C/cm\]            

    B)  \[{{15}^{o}}C/cm\]

    C)  \[{{25}^{o}}C/cm\]           

    D)  \[{{50}^{o}}C/cm\]

    Correct Answer: C

    Solution :

    \[\frac{\Delta Q}{\Delta t}=KA\frac{\Delta \theta }{\Delta x}\] Thermal gradient \[=\frac{\left( \frac{\Delta Q}{\Delta t} \right)}{KA}=\frac{10}{0.4}={{25}^{o}}C/cm\]


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