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  3. BCECE Medical

BCECE Medical BCECE Medical Solved Papers-2014

  • question_answer
    When a radioactive isotope \[_{88}{{R}^{228}}\] decays in series by the emission of \[3\alpha \]-particles and \[\beta \]-particles, the mass number of the isotope finally formed is

    A)  83                

    B)  72

    C)  216             

    D)  228

    Correct Answer: C

    Solution :

    Decrease in mass number due to emission of 3a-partides and p -particles                 \[=3\times 4=12\] Decrease in change number in the process                 \[=3\times 2-1=5\] Therefore, \[A=228-12=216\]


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