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BCECE Medical BCECE Medical Solved Papers-2015

  • question_answer
    A stream of water flowing horizontally with the speed of 15 \[m{{s}^{-1}}\] gushes out of a tube of cross-sectional area \[{{10}^{-2}}{{m}^{-2}}\] and hits a vertical wall nearby. What is the force exerted on the wall by the impact or water? Assuming it does not rebound.

    A)  2250 N            

    B)  2000 N

    C)  1500N            

    D)  1000N

    Correct Answer: A

    Solution :

    Area of cross-section of the tube, \[a={{10}^{-2}}{{m}^{2}}\]Speed of stream of water = 15 m/s V = Volume of water coming out per second from the tube \[=a\times v=15\times {{10}^{-2}}{{m}^{3}}{{s}^{-1}}\]. Also, we know that density of water striking the wall per second, then \[m=pV={{10}^{3}}\times 15\times {{10}^{-2}}kg{{s}^{-1}}=150\,kg{{s}^{-1}}\] As on hitting the wall, water does not reobound, so F = change in momentum per second = mass of water flowing out per second \[\times \]velocity \[=150\times 15=2250\,N\]


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