A) \[2\mu F\]
B) \[3\mu F\]
C) \[1\mu F\]
D) \[0.5\mu F\]
Correct Answer: A
Solution :
The circuit is shown in the figure. As points a and b are at same potential, so no charge flows through ab. Now two remaining capacitors are in parallel, hence \[{{C}_{eq}}=C+C=2C\] \[=2\times 1=2\mu F\]You need to login to perform this action.
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