A) \[2\times {{10}^{-5}}T\]
B) \[4\times {{10}^{-5}}T\]
C) \[8\times {{10}^{-5}}T\]
D) \[1.2\times {{10}^{-4}}T\]
Correct Answer: B
Solution :
\[{{B}_{1}}=\frac{{{\mu }_{0}}I}{4\pi a}(\sin {{\phi }_{1}}+\sin {{\phi }_{2}})\] \[\tan {{30}^{o}}=\frac{a}{\left[ \frac{l}{2} \right]}\] \[\Rightarrow \]\[a=\frac{1}{2\sqrt{3}}\]\[\Rightarrow \]\[{{B}_{1}}=\frac{{{\mu }_{0}}I}{4\pi \left( \frac{l}{2\sqrt{3}} \right)}(\sin {{60}^{o}}+\sin {{60}^{o}})\]\[\Rightarrow \] \[{{B}_{1}}=\frac{6{{\mu }_{0}}I}{4\pi l}\]\[\Rightarrow \] \[{{B}_{total}}=3{{B}_{1}}\]\[\Rightarrow \] \[{{B}_{total}}=4\times {{10}^{-5}}T\]You need to login to perform this action.
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