A) 60 min
B) 5 min
C) 7.5mm
D) 15 min
Correct Answer: D
Solution :
\[\lambda =\frac{2.303}{t}\log \frac{{{N}_{0}}}{N}\] \[=\frac{2.303}{30}\log \frac{1}{1-\frac{3}{4}}=\frac{2.303}{30}\log 4\] \[=0.0462\,{{\min }^{-1}}\] \[{{t}_{1/2}}=\frac{0.693}{\lambda }=\frac{0.693}{0.0462}\]You need to login to perform this action.
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