A) 590V
B) 690V
C) 790V
D) 890V
Correct Answer: C
Solution :
After combination of drops \[{{(R')}^{3}}=2{{R}^{3}}\] \[R'={{2}^{1/3}}R\] \[q'=2q\] Thus, \[V'=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{q'}{R'}\] \[=\frac{1}{4\pi {{\varepsilon }_{0}}}=\frac{2q}{{{2}^{1/3}}R}\] \[={{2}^{1/3}}V\] \[={{2}^{1/3}}(500)=790V\]You need to login to perform this action.
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