2. Solved Papers
  3. BVP Medical

BVP Medical BVP Medical Solved Paper-2000

  • question_answer
    A spring 40 mm long is stretched by the application of a force, if 10 N force is required to stretch the spring through 1 mm. Then work done in stretching the spring through 40 mm is :

    A)  8 J                                         

    B)  4 J

    C)  16 J                                       

    D)  32 J

    Correct Answer: A

    Solution :

                                                     Here, initial length of spring \[{{l}_{1}}=40\text{ }mm\] Force required to stretch the spring by 1 mm = 10 N Final stretch = 40 mm The force required to stretch the string by 40 mm is given by \[=10\times 40=400N\] Average force \[F=\frac{400}{2}=200N\] Hence work done is given by = Average force \[\times \] distance \[=200\times 40=8000\text{ }Nmm\] \[=8Nm=8J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner