A) \[1.05\times {{10}^{-34}}\,Js\]
B) \[2.05\times {{10}^{-34}}\,Js\]
C) \[3.10\times {{10}^{-34}}\,Js\]
D) \[4.05\times {{10}^{-34}}\,Js\]
Correct Answer: A
Solution :
Here, Initial orbit \[{{n}_{1}}=4\] Final orbit \[{{n}_{2}}=5\] Plancks constant \[h=6.6\times {{10}^{-34}}Js\] change in angular momentum is given by \[\Delta L={{L}_{2}}-{{L}_{1}}=\frac{{{n}_{2}}h}{2\pi }-\frac{{{n}_{1}}h}{2\pi }\] \[\Delta L=\frac{h}{2\pi }({{n}_{2}}-{{n}_{1}})=\frac{6.6\times {{10}^{-34}}}{2\times 3.14}\times (5-4)\] So, \[\Delta L=\frac{6.6\times {{10}^{-34}}\times 1}{3.14\times 2}=1.05\times {{10}^{-34}}Js\]
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