BVP Medical BVP Medical Solved Paper-2000

  • question_answer
    A lens of refractive index p. is dipped in a liquid of refractive index p of focal length of lens in air is \[f.\] Its focal length in liquid will be :

    A) \[\frac{f\mu (\mu -1)}{(\mu -\mu )}\]                   

    B) \[\frac{f(\mu -\mu )}{\mu (\mu -1)}\]

    C) \[\frac{\mu (\mu -1)}{f(\mu -\mu )}\]                   

    D) \[\frac{f\mu \mu }{\mu -\mu }\]

    Correct Answer: A

    Solution :

                                                                                          Using the relation \[\frac{1}{f}=\frac{\mu -1}{1}\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\]            ??.(1) \[\frac{1}{f}=\left( \frac{\mu -\mu }{\mu } \right)\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\]          ?..(2) So, by equation (1) by (2) we get \[\frac{f}{f}=\frac{\mu -1}{1}\times \frac{\mu }{\mu -\mu }\] or  \[f=\frac{f\mu (\mu -1)}{(\mu -\mu )}\]


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