BVP Medical BVP Medical Solved Paper-2000

  • question_answer
    Two trains, one coming towards and another going away from an observer both at 4 m/s produce whistle simultaneously of frequency 300 Hz. The number of beats produced, will be :

    A)  5                                            

    B)  6            

    C)  7                                            

    D)  12

    Correct Answer: C

    Solution :

                                                                      Number of beats produced is given by \[\Delta n=\left( \frac{\upsilon }{\upsilon -u}-\frac{\upsilon }{\upsilon +u} \right)n=\left( \frac{2\upsilon u}{{{\upsilon }^{2}}-{{u}^{2}}} \right)n\] or \[\Delta n=\frac{2\times 4\times 332}{{{(332)}^{2}}-{{(4)}^{2}}}\times 300\] or \[\Delta n=\frac{2656\times 300}{110224-16}=\frac{2656\times 300}{110208}=7.22\] \[\Delta n\approx 7\]


You need to login to perform this action.
You will be redirected in 3 sec spinner