A) 2.1volt
B) 4.2 volt
C) 1.5volt
D) None of these
Correct Answer: A
Solution :
First excitation energy of sodium will be \[E=hv=\frac{hc}{\lambda }=\frac{6.63\times {{10}^{-34}}\times 3\times {{10}^{8}}}{5896\times {{10}^{-10}}}\] \[E=0.00337\times {{10}^{-6}}J=3.37\times {{10}^{-19}}J\] \[E=\frac{3.37\times {{10}^{-19}}}{1.6\times {{10}^{-19}}}=2.1eV\] Hence, the first excitation potential of sodium atom is 2.1 volt.You need to login to perform this action.
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