A) 20 V
B) 10 V
C) 15 V
D) 5 V
Correct Answer: A
Solution :
Here: \[{{V}_{L}}=12V,{{V}_{R}}=16V\] The net potential difference across the circuit is given by \[E{{V}^{2}}={{V}_{L}}^{2}+{{V}_{R}}^{2}={{(12)}^{2}}+{{(16)}^{2}}\] \[EV=\sqrt{{{(12)}^{2}}+{{(16)}^{2}}}=\sqrt{400}\] \[EV=20V\]You need to login to perform this action.
You will be redirected in
3 sec