A) \[10\Omega \]
B) \[15\Omega \]
C) \[5\Omega \]
D) \[7.5\Omega \]
Correct Answer: A
Solution :
Electronegativity of halogens is in the order \[15\Omega \] F being most electronegative has stronger electron withdrawing effect (\[5\Omega \] effect) and hence stabilises the carboxylate ion to a greater extent. Thus order of strength \[7.5\Omega \] \[5896\overset{\text{o}}{\mathop{\text{A}}}\,\]
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