A) 36 day
B) 12.86 day
C) 24.20 day
D) 16.40 day
Correct Answer: D
Solution :
Time \[(T)=\frac{2.303\times {{t}^{1/2}}}{0.693}\log \frac{{{N}_{0}}}{N}\] \[=\frac{2.303\times 3.8}{0.693}\log \left( \frac{{{N}_{0}}}{{{N}_{0}}/20} \right)\] \[=\frac{2.303\times 3.8}{0.693}\log 20\] \[=16.4day\]
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