BVP Medical BVP Medical Solved Paper-2001

  • question_answer
    Self-inductance of a coil                is 5 mH. If a current of 2 A is flown. What is the magnetic flux through the coil?

    A)  0.04 weber                       

    B)  0.05 weber

    C)  0.2 weber                          

    D)  0.01 weber

    Correct Answer: A

    Solution :

                                                                      Using the relation for magnetic flux is \[\phi =Li\]                             ?...(1) (Here, \[i=2\text{ }amp,\text{ }L=5\text{ }mH=5\times {{10}^{-3\text{ }}}H\]) From equation (1) \[\phi =2\times 5\times {{10}^{-3}}\] \[=10\times {{10}^{-3}}=0.01weber\]


You need to login to perform this action.
You will be redirected in 3 sec spinner