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BVP Medical BVP Medical Solved Paper-2001

  • question_answer
    An electron and a positron each of mass \[\frac{1}{2000}\]amu annihilate each other and produce two photons of equal energy The minimum energy of each photon produced, will be :

    A)  0.0465 MeV                      

    B) 4.65 MeV

    C)  0.465 MeV                        

    D)  0.565 MeV

    Correct Answer: C

    Solution :

                                                                           Mass equivalent to each photon \[=\frac{1}{2000}amu\] Energy of each photon is \[=\frac{1}{2000}\times 931MeV\] \[=0.465MeV\]


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