A) \[9\times {{10}^{10}}J\]
B) \[9\times {{10}^{12}}J\]
C) \[9\times {{10}^{11}}J\]
D) \[9\times {{10}^{10}}J\]
Correct Answer: A
Solution :
Mass of \[_{92}{{U}^{235}}\] is changed into energy \[=0.1%\] from 1 kg of \[_{92}{{U}^{235}}\] mass converting into energy is \[m=\frac{0.1}{100}\times 1={{10}^{-3}}kg\] From Einstein equation \[E=m{{c}^{2}}\] Hence, energy \[E={{10}^{-3}}\times {{\left( 3\times {{10}^{8}} \right)}^{2}}\] \[=9\times {{10}^{13}}J\]
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